Formula Itungan HVAC

I, Suhu:

Celsius (C) jeung Fahrenheit (F)

Fahrenheit = 32 + Celsius × 1,8

Celsius = (Fahrenheit -32) /1.8

Kelvin (K) jeung Celsius (C)

Kelvin (K) = Celsius (C) +273,15

II, Konversi tekanan:

Mpa, Kpa, pa, bar

1 Mpa = 1000 Kpa;

1 Kpa = 1000 pa；

1 Mpa = 10 bar

1 bar = 0,1 Mpa = 100 Kpa;

1 atmosfir = 101,325 Kpa = 1 bar = 1 Kilogram;

1 bar = 14,5 psi

1 psi = 6,895 Kpa

1 kg/cm2=105=10 mH2O=1 bar=0,1 MPa

1 Pa = 0,1 mmH2O = 0,0001 mH2O

1 mH2O = 104 Pa = 10 kPa

III, Laju angin, konvérsi volume

1CFM = 1,699 M³/H=0,4719 l/s

1M³/H=0,5886CFM

1l/s=2.119CFM

1FPM = 0,3048 m / mnt = 0,00508 m / s

IV, kapasitas cooling jeung kakuatan:

1KW = 1000 W

1KW = 861 Kcal / h = 0,39 P (kapasitas cooling)

1W = 1 J/s

1USTR=3024Kcal/h=3517W(kapasitas cooling)

1 BTU = 0,252 kkal/jam = 1055J

1 BTU/H = 0,252 kkal/jam

1BTU/H=0.2931W(kapasitas cooling)

1MTU/H = 0.2931KW (kapasitas cooling)

1HP (listrik) = 0,75KW (listrik)

1KW (listrik) = 1.34HP (listrik)

1RT (kapasitas cooling) = 3.517KW (kapasitas cooling)

1KW (kapasitas cooling）= 3,412 MBH

1P (kapasitas cooling）=2200kcal/h=2,56KW

1 kkal/jam = 1,163 W

V,Pangadem hawaketebalan instalasi tur kapasitas cooling:

1.5mm2=12A-20A（2650~4500W） 1P~2P

2.5mm2=20-25A（4500~5500W） 2P

4mm2=25-32A（5500~7500W） 2P~3P

6mm2=32-40A（7500~8500W） 3P~4P

VI, Rumus itungan réfrigeran:

1, Pamilihan klep ékspansi: ton tiis + 1,25% sangu

2. Pencét kakuatan: 1P = 0.735kW

3, muatan refrigerant: Kapasitas cooling (KW) ÷ 3,516 x 0,58

4, Aliran cai tina hawa cooler: Cooling kapasitas (KW) ÷ bédana suhu ÷ 1,163

5, Laju aliran cai cooling tina mesin screw cai-tiis: Kapasitas cooling (KW) × 0.86÷ bédana suhu

6, Laju aliran cai cooling tina mesin screw cai-tiiscooling capacityKW+ press power) ×0.86÷ bédana suhu

7. Nilai pemanasan kotor QT = QS + QL

8. Pendingin hawa: QT = 0.24*∝*L*(h1-h2)

9, pendingin hawa panas anu signifikan: QS = Cp * ∝ * L * (T1-T2)

10, Panas latén tina cooling hawa: QL = 600 * ∝ * L * (W1-W2)

11,Cai katirisanvolume:L/sV1= Q1/(4,187△T1)

12, Volume cai cooling: L/sV2=Q2/(4.187△T2)=(3.516+KW/TR)TR,Q2=Q1+N=TR*3.516+KW/TR*TR=(3.516+KW/TR) *TR

13, efisiensi Refrigeration: EER = kapasitas Refrigeration (Mbtu / h) / konsumsi kakuatan (KW);COP = Kapasitas kulkas (KW) / konsumsi kakuatan (KW)

14, kinerja beban cooling parsial: NPLV = 1/(0.01/A+0.42/B+0.45/C+0.12/D)

15, Arus beban pinuh (tilu fase): FLA = N/√3 UCOSφ

16. Volume hawa seger: Lo = nV

17. Udarasuplai volume: L=Qs/〔Cp*∝*(T1-T2)〕

18, kakuatan kipas: N1 = L1 * H1 / (102 * n1 * n2)

19, Kakuatan pompa cai: N2 = L2 * H2 * r / (102 * n3 * n4)

20, Diaméter pipa: D = √4 * 1000L2 / (π * v)

21, Luas saluran: F=a*b*L1/(1000u)